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Conure pairing
- Thread starter Sazza22
- Start date
Monica
Cruising the avenue
Avenue Veteran
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Mayor of the Avenue
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As long as there are no splits.... you'll get normal males split turquoise, cinnamon and opaline.
Females will all be pineapples split turquoise.
Genetic Calculator 1.3 Green-cheeked Conure
Females will all be pineapples split turquoise.
Genetic Calculator 1.3 Green-cheeked Conure
This is a good site to give you an idea of what to expect.
Green-Cheeked Conure mutation colors prediction tables by The Feather Tree/ Steve Garvin
Green-Cheeked Conure mutation colors prediction tables by The Feather Tree/ Steve Garvin
Split means they carry a recessive gene, they will appear normal coloration but carry a copy of the gene for turquoise and if bred with another bird that is turquoise or split, you'll get some turquoise babies.
Monica
Cruising the avenue
Avenue Veteran
Celebirdy of the Month
Mayor of the Avenue
Avenue Spotlight Award
These would be your results, assuming no splits.
1.0 green cinnamon opaline(yellowsided) x 0.1 turquoise(parblue)
% from all 1.0
100.0% 1.0 green /turquoise(parblue) opaline(yellowsided)-cinnamon
% from all 0.1
100.0% 0.1 green opaline(yellowsided) cinnamon /turquoise(parblue)
Without the "mumbo jumbo"....
1.0 green cinnamon opaline(yellowsided) x 0.1 turquoise(parblue)
% from all 1.0
100.0% 1.0 green
% from all 0.1
100.0% 0.1 green opaline(yellowsided) cinnamon
In other words, all male offspring will be green/normal split to turquoise. They need 2 turquoise genes to be visual, but since they only have 1, they are considered split for the mutation. The males will also be split for cinnamon and opaline.
There is no visual way to tell if they are split for these mutations, you can only know by knowing their genetic background or pairing with a known bird... i.e. pairing one of the male offspring with a turquoise hen. You get turquoise colored and normal colored offspring, then you know the male is split turquoise. If no turquoise offspring when paired to a turquoise hen, then you know the male isn't split for the mutation.
Since we know that the hen is turquoise, all offspring will be split for the mutation. (males and females)
If you get any turquoise colored offspring (i.e. turquoise males and turquoise pineapple females), then you know the male is split for turquoise.
1.0 green cinnamon opaline(yellowsided) x 0.1 turquoise(parblue)
% from all 1.0
100.0% 1.0 green /turquoise(parblue) opaline(yellowsided)-cinnamon
% from all 0.1
100.0% 0.1 green opaline(yellowsided) cinnamon /turquoise(parblue)
Without the "mumbo jumbo"....
1.0 green cinnamon opaline(yellowsided) x 0.1 turquoise(parblue)
% from all 1.0
100.0% 1.0 green
% from all 0.1
100.0% 0.1 green opaline(yellowsided) cinnamon
In other words, all male offspring will be green/normal split to turquoise. They need 2 turquoise genes to be visual, but since they only have 1, they are considered split for the mutation. The males will also be split for cinnamon and opaline.
There is no visual way to tell if they are split for these mutations, you can only know by knowing their genetic background or pairing with a known bird... i.e. pairing one of the male offspring with a turquoise hen. You get turquoise colored and normal colored offspring, then you know the male is split turquoise. If no turquoise offspring when paired to a turquoise hen, then you know the male isn't split for the mutation.
Since we know that the hen is turquoise, all offspring will be split for the mutation. (males and females)
If you get any turquoise colored offspring (i.e. turquoise males and turquoise pineapple females), then you know the male is split for turquoise.
